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                ## React-Router相關問題 1. #### 如何使用JS代碼,來動態控制路由的跳轉? React-Router 返回的組件,屬性里面有 history 變量,實現跳轉的代碼如下 `this.props.history.pushState(null, '/user' ) ` 2. #### React-Router二級路由,路由匹配返回的組件問題? 如果項目規模不是太小的話,就會存在一級模塊,二級模塊,亦或是三級模塊。 如 `127.0.0.1:3000/#/user/detail` 這樣的的路由,返回的detail組件,是掛在 一級模塊 user 上的。 那么問題來了, 1. /user路由**有**相對應的組件 2. /user路由**沒有**相對應的組件 **情況1:** `/user/detail` 返回的組件 ,在 **user 對應組件**的 `this.props.children` 屬性中 **情況2:** `/user/detail` 返回的組件,在 **/ 對應的組件**的 `this.props.children` 屬性中 ``` //情況1代碼: module.exports = { path: 'user', //子路由 getChildRoutes(location, cb) { require.ensure([], (require) => { cb(null, [ require('./routes/test1') ]) }) }, //當前路由返回的控件 getComponent(location, cb) { require.ensure([], (require) => { console.log('user', location) cb(null, require('./components')) }) } } ``` ``` //情況2代碼: module.exports = { path: 'authority', //子路由 getChildRoutes(location, cb) { require.ensure([], (require) => { cb(null, [ require('./authoritysp'), require('./datapolicy'), require('./list') ]) }) } } ```
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