[TOC] #### 類通訊錄數據結構處理 1. 服務端數據結構  2. 處理排序，得到一維數組 ~~~ _normalizeSinger(list) { let map = { hot: { title: HOT_NAME, items: [] } } list.forEach((item, index) => { // 取前10條作為熱門數據 if (index < HOT_SINGER_LEN) { map.hot.items.push(new Singer({ name: item.Fsinger_name, id: item.Fsinger_mid })) } const key = item.Findex if (!map[key]) { map[key] = { title: key, items: [] } } map[key].items.push(new Singer({ name: item.Fsinger_name, id: item.Fsinger_mid })) }) // 為了得到有序列表，我們需要處理 map let ret = [] let hot = [] for (let key in map) { let val = map[key] if (val.title.match(/[a-zA-Z]/)) { ret.push(val) } else if (val.title === HOT_NAME) { hot.push(val) } } ret.sort((a, b) => { return a.title.charCodeAt(0) - b.title.charCodeAt(0) }) return hot.concat(ret) } ~~~