# Safecracker
##### Time Limit : 2000/1000ms (Java/Other)???Memory Limit : 65536/32768K (Java/Other)
##### Total Submission(s) : 3???Accepted Submission(s) : 1
Problem Description
=== Op tech briefing, 2002/11/02 06:42 CST ===
"The item is locked in a Klein safe behind a painting in the second-floor library. Klein safes are extremely rare; most of them, along with Klein and his factory, were destroyed in World War II. Fortunately old Brumbaugh from research knew Klein's secrets and wrote them down before he died. A Klein safe has two distinguishing features: a combination lock that uses letters instead of numbers, and an engraved quotation on the door. A Klein quotation always contains between five and twelve distinct uppercase letters, usually at the beginning of sentences, and mentions one or more numbers. Five of the uppercase letters form the combination that opens the safe. By combining the digits from all the numbers in the appropriate way you get a numeric target. (The details of constructing the target number are classified.) To find the combination you must select five letters v, w, x, y, and z that satisfy the following equation, where each letter is replaced by its ordinal position in the alphabet (A=1, B=2, ..., Z=26). The combination is then vwxyz. If there is more than one solution then the combination is the one that is lexicographically greatest, i.e., the one that would appear last in a dictionary."
v - w^2 + x^3 - y^4 + z^5 = target
"For example, given target 1 and letter set ABCDEFGHIJKL, one possible solution is FIECB, since 6 - 9^2 + 5^3 - 3^4 + 2^5 = 1. There are actually several solutions in this case, and the combination turns out to be LKEBA. Klein thought it was safe to encode the combination within the engraving, because it could take months of effort to try all the possibilities even if you knew the secret. But of course computers didn't exist then."
=== Op tech directive, computer division, 2002/11/02 12:30 CST ===
"Develop a program to find Klein combinations in preparation for field deployment. Use standard test methodology as per departmental regulations. Input consists of one or more lines containing a positive integer target less than twelve million, a space, then at least five and at most twelve distinct uppercase letters. The last line will contain a target of zero and the letters END; this signals the end of the input. For each line output the Klein combination, break ties with lexicographic order, or 'no solution' if there is no correct combination. Use the exact format shown below."
?
Sample Input
~~~
1 ABCDEFGHIJKL
11700519 ZAYEXIWOVU
3072997 SOUGHT
1234567 THEQUICKFROG
0 END
~~~
?
Sample Output
~~~
LKEBA
YOXUZ
GHOST
no solution
~~~
1.lexicographical order:cap < card < cat < to < too< two < up
2.其實是個組合問題12*11*10*9*8大約十幾萬次當然5個循環不超時,用搜索的形式寫的時候因為遞歸和回溯耗時,所以超時
3.代碼:
~~~
#include<cstdio>
#include<cstring>
#include<algorithm>
using namespace std;
int t;
char s[20];
int a[10];
int len;
bool flag;
int cmp(int a,int b)
{
return a>b;
}
void Find()
{
for(int i=1; i<=len; i++)
{
a[1]=s[i]-'A'+1;
for(int j=1; j<=len; j++)
{
if(i==j)
continue;
a[2]=s[j]-'A'+1;
for(int k=1; k<=len; k++)
{
if(j==k||k==i)
continue;
a[3]=s[k]-'A'+1;
for(int l=1; l<=len; l++)
{
if(l==k||l==j||l==i)
continue;
a[4]=s[l]-'A'+1;
for(int m=1; m<=len; m++)
{
if(m==l||m==k||m==j||m==i)
continue;
a[5]=s[m]-'A'+1;
if(a[1]-a[2]*a[2]+a[3]*a[3]*a[3]-a[4]*a[4]*a[4]*a[4]+a[5]*a[5]*a[5]*a[5]*a[5]==t)
{
flag=1;
break;
}
}
if(flag)
break;
}
if(flag)
break;
}
if(flag)
break;
}
if(flag)
break;
}
}
int main()
{
while(scanf("%d%s",&t,s+1)==2)
{
if(t==0&&strcmp("END",s+1)==0)
{
break;
}
else
{
len=strlen(s+1);
flag=0;
sort(s+1,s+1+len,cmp);//保證答案是字典序上最大
Find();
if(flag)
printf("%c%c%c%c%c\n",a[1]+'A'-1,a[2]+'A'-1,a[3]+'A'-1,a[4]+'A'-1,a[5]+'A'-1);
else
printf("no solution\n");
}
}
return 0;
}
~~~
- 前言
- The 12th Zhejiang Provincial Collegiate Programming Contest - D
- 用鄰接表存儲n個頂點m條弧的有向圖
- hdu 5289 Assignment(給一個數組,求有多少個區間,滿足區間內的最大值和最小值之差小于k)
- hdu 1358 Period(給定一個字符串,求有多少個前綴(包括自己本身),它是由k(k&gt;2,并且盡量大)個循環節組成的)
- hdu 1806 Frequent values(給定一個非降序數組,求任意區間內出現次數最多的數的次數)
- poj 3264 Balanced Lineup(查詢區間最大值與最小值的差)
- HDU 1010 Tempter of the Bone(DFS+奇偶剪枝)
- HDU 1015 Safecracker(第一次用了搜索去遍歷超時,第二次用for循環可以了,思路一樣的)
- HDU 1016 Prime Ring Problem(DFS)
- HDU 1026 Ignatius and the Princess I(BFS+記錄路徑)
- HDU 1072 Nightmare(BFS)
- HDU 1237 簡單計算器(后綴式+棧)