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                [TOC] ## fish shell判斷某個變量是否存在 fish shell 判斷變量是否存在直接使用 `test 變量`就可以,然后我們使用`and`和`or`實現if..else..的邏輯。如下所示:<br/> ```bash #!/usr/bin/env fish set a 1 set b 3 test $a -gt $b ;and echo "a>b" ;or echo "a<=b" test $c ;and echo "存在變量a";or echo "不存在變量c" ``` ![Image](https://img.kancloud.cn/ed/c0/edc06b12a86417b3d7bd1003b0a93929_491x180.png) 上面的腳本使用`and`和`or`實現了`if..else..`的邏輯,是腳本更簡潔。<br/> 因此,使用fish寫含有參數傳遞的腳本時,可以使用上面提及到的方法,先判斷參數是否存在,然后匹配參數在作出相應的執行。如下例子:<br/> ```bash #!/usr/bin/env fish if test $argv[1];and test $argv[1] = "help" echo "成功匹配到 help" else echo "未匹配到你輸入的參數" end ``` ![Image](https://img.kancloud.cn/73/0d/730d7f6534d7fefe65d39eb257c86df0_415x162.png) 之所以要使用test判斷參數是否存在是因為,fish shell在變量不存在時進行匹配,將會報錯,或者警告,所以這樣做很有必要! ## bash shell如何判斷參數是否存在 bash中并不用and和or,而是使用`&&`和`||`來實現if..else..的流程控制,如下: ```bash #!/bin/bash a=1 b=2 test $a -gt $b && echo "a>b" || echo "a<=b" ``` ![Image](https://img.kancloud.cn/44/22/4422b74c862e51acfdde51ca115e102d_384x79.png) ```bash #!/bin/bash a=1 b=2 test $a -gt $b && echo "a>b" || echo "a<=b" test $1 && echo "腳本至少輸入了一個參數" || echo "腳本沒有輸入參數" test $2 && echo "腳本輸入了第2個參數" || echo "腳本沒有輸入第2個參數" ``` ![Image](https://img.kancloud.cn/89/7a/897af1abcf712283cf8f10e1ca680024_451x115.png) <br/> 于是我們可以這樣來進行條件判斷,這樣基本統一了fish和bash這兩種shell,不會記混了!<br/> ```bash #!/bin/bash if test $1 && test $1 = "hello" ;then echo "$1" else echo "無法解析輸入" fi ``` ![Image](https://img.kancloud.cn/90/fc/90fc60f1a878a32416902ed0a2c38440_400x120.png)
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