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                # 編寫`test2.c` ```c #include <stdio.h> int main(int argc, char const *argv[]) { int i = 2; int j = 3; int sum = i + j; printf("%d\n", sum); return 0; } ``` # 編譯運行 ```javascript zhoumengkang@bogon:~/Downloads$ gcc test2.c -o test2 zhoumengkang@bogon:~/Downloads$ ./test2 5 ``` # 內存初探 我們習慣用16進制來表示內存地址,我當前電腦為64位的,所以內存的地址空間范圍為`64個0`~`64個1`的跨度,但是我們只用48位,用十六進制表示就是 ```javascript 0x000000000000 0xffffffffffff ``` ## 為什么64位機指針只用48個位? > https://www.zhihu.com/question/28638698 > https://stackoverflow.com/questions/6716946/why-do-64-bit-systems-have-only-a-48-bit-address-space # 代碼完善`test2.c` ```c #include <stdio.h> int main(int argc, char const *argv[]) { int i = 2; int j = 3; int sum = i + j; printf("%d\n", sum); // 增加內存輸出測試 printf("i addr is: %p\n",&i); printf("j addr is: %p\n",&j); printf("sum addr is: %p\n",&sum); return 0; } ``` # 編譯運行 ```javascript zhoumengkang@bogon:~/Downloads$ gcc test2.c -o test2 zhoumengkang@bogon:~/Downloads$ ./test2 5 i addr is: 0x7fff5ab02adc j addr is: 0x7fff5ab02ad8 sum addr is: 0x7fff5ab02ad4 ``` 我們可以通過`sizeof`來查看每個變量占用的內存大小 ```c printf("i size\t%lu",sizeof(i)); // 4 ``` 由此可見`i`,`j`,`sum`的地址是連續的,而且是先分配的地址的值更大。 棧的內存分布就是自上而下的。 先到這里。
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