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                ### 這道題很容易可以想到后進先出的數據結構 ---- 棧,因為我們沒有 m_prev 指針。所以遍歷時,把節點壓棧就好。(這道題用遞歸代碼也很好寫) 下面是代碼實現(迭代): ``` #include <stack> void printInverse(SList *pHead) { if (pHead == nullptr) { return nullptr; } std::stack<SList *> nodeStack; // 將遍歷到的節點入棧 while (pHead != nullptr) { nodeStack.push(pHead); pHead = pHead->m_next; } // 出棧打印 while (!nodeStack.empty()) { SList *topNode = nodeStack.top(); nodeStack.pop(); std::cout << topNode->m_data << " "; } std::cout << endl; } ```
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