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                企業??AI智能體構建引擎,智能編排和調試,一鍵部署,支持知識庫和私有化部署方案 廣告
                使用兩個stack,如進入隊列為 1,2,3,4,5 那么其中的一個棧A內保存了 [棧底]5,4,3,2,1 ,這樣出隊列是順序與入隊列一直,假如此時6要入隊列,如何使得棧A為 :[棧底]6,5,4,3,2,1,可以先將A [棧底]5,4,3,2,1 出棧入棧到另一個空的棧B中:[棧底]1,2,3,4,5,然后6入棧B,之后B再出棧入棧到另一個原來的棧A中,這樣A[棧底]6,5,4,3,2,1 ``` public class MyQueue { private Stack<Integer> stack1 = null; private Stack<Integer> stack2 = null; public MyQueue() { stack1 = new Stack<Integer>(); stack2 = new Stack<Integer>(); } /* * @param element: An integer * @return: nothing */ public void push(int element) { Stack<Integer> empty = stack1.isEmpty()?stack1:stack2; Stack<Integer> notEmpty = empty == stack1? stack2 : stack1; while(!notEmpty.isEmpty()) {//A棧出棧入B棧 Integer cur = notEmpty.pop(); empty.push(cur); } empty.push(element); while(!empty.isEmpty()) {//B棧出棧入A棧 Integer cur = empty.pop(); notEmpty.push(cur); } } /* * @return: An integer */ public int pop() { Stack<Integer> empty = stack1.isEmpty()?stack1:stack2; Stack<Integer> notEmpty = empty == stack1? stack2 : stack1; if(empty.isEmpty() && notEmpty.isEmpty()) { return -1; } return notEmpty.pop(); } /* * @return: An integer */ public int top() { Stack<Integer> empty = stack1.isEmpty()?stack1:stack2; Stack<Integer> notEmpty = empty == stack1? stack2 : stack1; if(empty.isEmpty() && notEmpty.isEmpty()) { return -1; } return notEmpty.peek(); } } ```
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