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## 二叉樹的各種計算公式

1. `n`個節點的二叉樹一共有`((2n)!)/(n! * (n+1)!)`種

2. `n`層二叉樹的第n層最多為`2^(n-1)`個

3. 二叉樹節點計算公式 `N = n0+n1+n2`，度為`0`的葉子節點比度為`2`的節點數多一個。`N=1*n1+2*n2+1`

4. 對任何一棵二叉樹T，如果其終端節點數為`n0`，度為`2`的節點數為`n2`，則`n0=n2+1`

5. 具有`n`個節點的完全二叉樹的深度為`log2(n) + 1`
                    
                
        
                
            
        
                
    
                
    
                
        
                
    
                

                







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