#### html頁面需要加入
~~~
<meta http-equiv="Access-Control-Allow-Origin" content="" />
<meta http-equiv="content-security-policy" />
~~~
#### php端需要加
~~~
header('Access-Control-Allow-Origin:*');
~~~
#### jsonp ajax可以這樣寫
~~~
var href='http://qxu1142200245.my3w.com/index.php/Home/Login/login';
jQuery.ajax({
url:href,
data:{
username:account,
password:password
},
dataType: "jsonp",
success: function(json){
if(json.status==1){
mui.toast(json.info);
localStorage.setItem('username',account);
mui.openWindow({
id:'home',
url:'home.html',
show:{
aniShow:'pop-in'
},
waiting:{
autoShow:true
}
});
}else{
mui.toast(json.info);
}
},
error: function(XMLHttpRequest, textStatus, errorThrown) {
alert(XMLHttpRequest.status);
alert(XMLHttpRequest.readyState);
alert(textStatus);
}
})
~~~
#### thinkphp 后端可以這樣哦
~~~
public function login(){
//if(!IS_AJAX) $this->error('頁面不存在');
$username=I('get.username');
$password=md5(I('get.password'));
$userDb=M('user')->where(array('username'=>$username))->find();
if($userDb['password']!=$password){
$data=array(
'info'=>'用戶名或密碼不正確',
'status'=>0,
);
$this->ajaxReturn($data,'jsonp');
}else{
$data=array(
'info'=>'登錄成功！正在跳轉',
'status'=>1,
);
$this->ajaxReturn($data,'jsonp');
}
}
~~~
