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                合規國際互聯網加速 OSASE為企業客戶提供高速穩定SD-WAN國際加速解決方案。 廣告
                >[info] 求1+2!+3!+...+20!的和。 ~~~C #include <stdio.h> int main() { int i; long double k=1,sum=0; for(i=1;i<=20;i++){ k*=i; sum+=k; } /**錯誤,且這樣二次循環進行乘法導致效率很低 for(i=1;i<=20;i++){ for(j=i;j>0;j--){ k*=j; sum+=k; } k=1; } **/ printf("%Lf\n", sum); return 0; } ~~~
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