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                合規國際互聯網加速 OSASE為企業客戶提供高速穩定SD-WAN國際加速解決方案。 廣告
                >[info]求一個3*3矩陣對角線元素之和 ~~~C #include <stdio.h> #define N 3 int main() { int i,j,a[N][N],sum=0; printf("input [3*3]:\n"); for(i=0;i<N;i++){ for(j=0;j<N;j++) scanf("%d", &a[i][j]); } for(i=0;i<N;i++){ sum+=a[i][i]; } printf("總和是%d\n", sum); return 0; } ~~~
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