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                ## [965\. 單值二叉樹](https://leetcode-cn.com/problems/univalued-binary-tree/) >Easy #### 思路 判斷有沒有其他數字,那肯定就是要遍歷二叉樹。記錄節點值,判斷當前節點是否與其他的節點不同。遍歷二叉樹,也就是深度優先和廣度優先,這邊選用DFS。 嘗試寫一下代碼,AC! #### 代碼 python3 ``` class Solution: def dfs(self, val, node): if node is None: return True if node.val != val: return False return self.dfs(val, node.left) and self.dfs(val, node.right) def isUnivalTree(self, root: TreeNode) -> bool: if root is None: return True val = root.val return self.dfs(val, root) ```
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