<ruby id="bdb3f"></ruby>

    <p id="bdb3f"><cite id="bdb3f"></cite></p>

      <p id="bdb3f"><cite id="bdb3f"><th id="bdb3f"></th></cite></p><p id="bdb3f"></p>
        <p id="bdb3f"><cite id="bdb3f"></cite></p>

          <pre id="bdb3f"></pre>
          <pre id="bdb3f"><del id="bdb3f"><thead id="bdb3f"></thead></del></pre>

          <ruby id="bdb3f"><mark id="bdb3f"></mark></ruby><ruby id="bdb3f"></ruby>
          <pre id="bdb3f"><pre id="bdb3f"><mark id="bdb3f"></mark></pre></pre><output id="bdb3f"></output><p id="bdb3f"></p><p id="bdb3f"></p>

          <pre id="bdb3f"><del id="bdb3f"><progress id="bdb3f"></progress></del></pre>

                <ruby id="bdb3f"></ruby>

                合規國際互聯網加速 OSASE為企業客戶提供高速穩定SD-WAN國際加速解決方案。 廣告
                yacc.py沒有構造抽像語法樹的特殊方法。不過,你可以自己很簡單的構造出來。 一個最為簡單的構造方法是為每個語法規則創建元組或者字典,并傳遞它們。有很多中可行的方案,下面是一個例子: ~~~ def p_expression_binop(p): '''expression : expression PLUS expression | expression MINUS expression | expression TIMES expression | expression DIVIDE expression''' p[0] = ('binary-expression',p[2],p[1],p[3]) def p_expression_group(p): 'expression : LPAREN expression RPAREN' p[0] = ('group-expression',p[2]) def p_expression_number(p): 'expression : NUMBER' p[0] = ('number-expression',p[1]) ~~~ 另一種方法可以是為不同的抽象樹節點創建一系列的數據結構,并賦值給p[0]: ~~~ class Expr: pass class BinOp(Expr): def __init__(self,left,op,right): self.type = "binop" self.left = left self.right = right self.op = op class Number(Expr): def __init__(self,value): self.type = "number" self.value = value def p_expression_binop(p): '''expression : expression PLUS expression | expression MINUS expression | expression TIMES expression | expression DIVIDE expression''' p[0] = BinOp(p[1],p[2],p[3]) def p_expression_group(p): 'expression : LPAREN expression RPAREN' p[0] = p[2] def p_expression_number(p): 'expression : NUMBER' p[0] = Number(p[1]) ~~~ 這種方式的好處是在處理復雜語義時比較簡單:類型檢查、代碼生成、以及其他針對樹節點的功能。 為了簡化樹的遍歷,可以創建一個通用的樹節點結構,例如: ~~~ class Node: def __init__(self,type,children=None,leaf=None): self.type = type if children: self.children = children else: self.children = [ ] self.leaf = leaf def p_expression_binop(p): '''expression : expression PLUS expression | expression MINUS expression | expression TIMES expression | expression DIVIDE expression''' p[0] = Node("binop", [p[1],p[3]], p[2]) ~~~
                  <ruby id="bdb3f"></ruby>

                  <p id="bdb3f"><cite id="bdb3f"></cite></p>

                    <p id="bdb3f"><cite id="bdb3f"><th id="bdb3f"></th></cite></p><p id="bdb3f"></p>
                      <p id="bdb3f"><cite id="bdb3f"></cite></p>

                        <pre id="bdb3f"></pre>
                        <pre id="bdb3f"><del id="bdb3f"><thead id="bdb3f"></thead></del></pre>

                        <ruby id="bdb3f"><mark id="bdb3f"></mark></ruby><ruby id="bdb3f"></ruby>
                        <pre id="bdb3f"><pre id="bdb3f"><mark id="bdb3f"></mark></pre></pre><output id="bdb3f"></output><p id="bdb3f"></p><p id="bdb3f"></p>

                        <pre id="bdb3f"><del id="bdb3f"><progress id="bdb3f"></progress></del></pre>

                              <ruby id="bdb3f"></ruby>

                              哎呀哎呀视频在线观看