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                >[danger]第一題:0字符串,每次只能刪含有相同元素的連續子串,最少刪多少次能刪成空串; ????這道題ac了,解法是先求連續子串的個數,對個數除以2向下取整加1 ????(每次必須從最中間先刪,所以就相當于最中間那個連續子串是電燈泡,刪掉電燈泡,兩邊就能有合并的機會,那么接下來每一次刪除就等同于刪掉合并了的兩個連續子串,歸納一下就是上面的解法)
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