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                判斷鏈表是否有環可以使用快慢指針的方法。如果鏈表中存在環,那么快慢指針最終會相遇;如果不存在環,則快指針會先到達鏈表的末尾。 以下是用 JavaScript 實現鏈表有環判斷的代碼: ```javascript function hasCycle(head) { if (head === null || head.next === null) { return false; } let slow = head; let fast = head.next; while (slow !== fast) { if (fast === null || fast.next === null) { return false; } slow = slow.next; fast = fast.next.next; } return true; } ``` 在這段代碼中,我們使用了兩個指針 `slow` 和 `fast`,開始時它們都指向鏈表的頭節點 `head`。每次迭代中,慢指針 `slow` 前進一步,快指針 `fast` 前進兩步。如果鏈表中存在環,那么快慢指針最終會相遇,返回 `true`;否則,快指針會先到達鏈表的末尾,返回 `false`。 注意,我們需要考慮特殊情況,即鏈表為空或者只有一個節點的情況,在這種情況下是不存在環的,直接返回 `false`。
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