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                一個農民手中有100元,想買100只雞回來喂養,公雞每只4元,母雞每只3元,小雞每只0.5元,希望你來幫助下這位農民伯伯,給他提供集中方案。 我一看到這樣的問題比較傻,就想著公雞的數量從1到100列舉遍,母雞也是,小雞也是如此,后來一想這樣列舉會累死人的,仔細一想,100元最多可以買到33值母雞,公雞為25,那么小雞的數量就是從這100只中減去母雞和公雞的數量即可, ~~~ public class chickenProblem { public static void main(String args[]) { int i,j,k;//i為母雞,j為公雞,k為小雞 int L=1; for(i=1;i<=33;i++) { for(j=1;j<=25;j++){ k=100-i-j; if(i*3+j*4+k*0.5==100) { System.out.println("方案"+L+":"+"母雞的數量為:"+i+","+"公雞的數量為:"+j+","+"小雞的數量為:"+k); L++; } } } } } 方案1:母雞的數量為:6,公雞的數量為:10,小雞的數量為:84 方案2:母雞的數量為:13,公雞的數量為:5,小雞的數量為:82 ~~~
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