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                ??碼云GVP開源項目 12k star Uniapp+ElementUI 功能強大 支持多語言、二開方便! 廣告
                There is a robot starting at position (0, 0), the origin, on a 2D plane. Given a sequence of its moves, judge if this robot ends up at (0, 0) after it completes its moves. The move sequence is represented by a string, and the character moves[i] represents its ith move. Valid moves are R (right), L (left), U (up), and D (down). If the robot returns to the origin after it finishes all of its moves, return true. Otherwise, return false. Note: The way that the robot is "facing" is irrelevant. "R" will always make the robot move to the right once, "L" will always make it move left, etc. Also, assume that the magnitude of the robot's movement is the same for each move. Example 1: ``` Input: "UD" Output: true Explanation: The robot moves up once, and then down once. All moves have the same magnitude, so it ended up at the origin where it started. Therefore, we return true. ``` Example 2: ``` Input: "LL" Output: false Explanation: The robot moves left twice. It ends up two "moves" to the left of the origin. We return false because it is not at the origin at the end of its moves. ``` ``` /** * @param {string} moves * @return {boolean} */ var judgeCircle = function(moves) { var x = 0; var y = 0; for(var i = 0; i < moves.length; i++){ if(moves.charAt(i) === 'R'){ x++; } if(moves.charAt(i) === 'L'){ x--; } if(moves.charAt(i) === 'U'){ y++; } if(moves.charAt(i) === 'D'){ y--; } } if( x===0 && y===0){ return true; } else{return false;} }; ```
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