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                ??碼云GVP開源項目 12k star Uniapp+ElementUI 功能強大 支持多語言、二開方便! 廣告
                Given a non-empty array of integers, every element appears twice except for one. Find that single one. Note: Your algorithm should have a linear runtime complexity. Could you implement it without using extra memory? Example 1: ``` Input: [2,2,1] Output: 1 ``` Example 2: ``` Input: [4,1,2,1,2] Output: 4 ``` ``` // 如果a、b兩個值不相同,則異或結果為1。如果a、b兩個值相同,異或結果為0。 // 利用0和任何數異或都為該數定理 var singleNumber = function(nums) { sum=0; for(var i=0;i<nums.length;i++){ sum^=nums[i]; } return sum; }; ```
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