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                ## 基礎練習 特殊的數字 ? 時間限制:1.0s ? 內存限制:512.0MB ? 問題描述   153是一個非常特殊的數,它等于它的每位數字的立方和,即153=1*1*1+5*5*5+3*3*3。編程求所有滿足這種條件的三位十進制數。 輸出格式   按從小到大的順序輸出滿足條件的三位十進制數,每個數占一行。 ~~~ // 特殊的數字 #include <iostream> using namespace std; int main() { int num,i,j,k; for(num=100;num<1000;++num) { i=num/100; k=num%10; j=(num-i*100-k)/10; if(num==i*i*i+j*j*j+k*k*k) cout<<num<<endl; } return 0; } ~~~
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