# 23.1\. Employer（雇主)/Employee(雇員) 下面關于`Employer` 和 `Employee`的關系模型使用了一個真實的實體類 (`Employment`)來表述，這是因為對于相同的雇員和雇主可能會有多個雇傭時間段。 對于金額和雇員姓名，用Components建模。  映射文件可能是這樣: ``` <hibernate-mapping> <class name="Employer" table="employers"> <id name="id"> <generator class="sequence"> <param name="sequence">employer_id_seq</param> </generator> </id> <property name="name"/> </class> <class name="Employment" table="employment_periods"> <id name="id"> <generator class="sequence"> <param name="sequence">employment_id_seq</param> </generator> </id> <property name="startDate" column="start_date"/> <property name="endDate" column="end_date"/> <component name="hourlyRate" class="MonetaryAmount"> <property name="amount"> <column name="hourly_rate" sql-type="NUMERIC(12, 2)"/> </property> <property name="currency" length="12"/> </component> <many-to-one name="employer" column="employer_id" not-null="true"/> <many-to-one name="employee" column="employee_id" not-null="true"/> </class> <class name="Employee" table="employees"> <id name="id"> <generator class="sequence"> <param name="sequence">employee_id_seq</param> </generator> </id> <property name="taxfileNumber"/> <component name="name" class="Name"> <property name="firstName"/> <property name="initial"/> <property name="lastName"/> </component> </class> </hibernate-mapping> ``` 用`SchemaExport`生成表結構。 ``` create table employers ( id BIGINT not null, name VARCHAR(255), primary key (id) ) create table employment_periods ( id BIGINT not null, hourly_rate NUMERIC(12, 2), currency VARCHAR(12), employee_id BIGINT not null, employer_id BIGINT not null, end_date TIMESTAMP, start_date TIMESTAMP, primary key (id) ) create table employees ( id BIGINT not null, firstName VARCHAR(255), initial CHAR(1), lastName VARCHAR(255), taxfileNumber VARCHAR(255), primary key (id) ) alter table employment_periods add constraint employment_periodsFK0 foreign key (employer_id) references employers alter table employment_periods add constraint employment_periodsFK1 foreign key (employee_id) references employees create sequence employee_id_seq create sequence employment_id_seq create sequence employer_id_seq ```