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                # C 程序:使用指針,遞歸和函數來查找數組元素的總和 > 原文: [https://beginnersbook.com/2014/06/c-program-to-find-sum-of-array-elements-using-pointers-recursion-functions/](https://beginnersbook.com/2014/06/c-program-to-find-sum-of-array-elements-using-pointers-recursion-functions/) 在本教程中,我們將學習以下兩種方法來找出數組元素的總和: 1)使用遞歸 2)使用指針 ### 方法 1:使用遞歸的數組元素的總和:函數調用自身 該程序調用用戶定義的函數`sum_array_elements()`,函數以遞歸方式調用自身。這里我們對數組元素進行了硬編碼,但是如果你想讓用戶輸入值,你可以使用`for`循環和`scanf`函數,就像我在本文的下一節(方法 2:使用指針)中所做的那樣。 ```c #include<stdio.h> int main() { int array[] = {1,2,3,4,5,6,7}; int sum; sum = sum_array_elements(array,6); printf("\nSum of array elements is:%d",sum); return 0; } int sum_array_elements( int arr[], int n ) { if (n < 0) { //base case: return 0; } else{ //Recursion: calling itself return arr[n] + sum_array_elements(arr, n-1); } } ``` 輸出: ```c Sum of array elements is:28 ``` ### 方法 2:使用指針的數組元素的總和 這里我們設置指向數組基址的指針然后我們遞增指針并使用`*`運算符來獲取和匯總所有數組元素的值。 ```c #include<stdio.h> int main() { int array[5]; int i,sum=0; int *ptr; printf("\nEnter array elements (5 integer values):"); for(i=0;i<5;i++) scanf("%d",&array[i]); /* array is equal to base address * array = &array[0] */ ptr = array; for(i=0;i<5;i++) { //*ptr refers to the value at address sum = sum + *ptr; ptr++; } printf("\nThe sum is: %d",sum); } ``` 輸出: ```c Enter array elements (5 integer values): 1 2 3 4 5 The sum is: 15 ```
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