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                # C++ 中的結構 > 原文: [https://beginnersbook.com/2017/09/cpp-structures/](https://beginnersbook.com/2017/09/cpp-structures/) 結構是一種復合數據類型,包含不同類型的不同變量。例如,您要存儲學生詳細信息,例如學生姓名,學生卷數,學生年齡。你有兩種方法可以做到這一點,一種方法是為每個數據創建不同的變量,但這種方法的缺點是,如果你想存儲多個學生的細節,那么在這種情況下,為每個學生創建單獨的一組變量是不可行的。 第二種是通過創建這樣的結構來實現它,也是最好的方法: ```cpp struct Student { char stuName[30]; int stuRollNo; int stuAge; }; ``` 現在這三個成員組合起來就像一個單獨的變量,你可以像這樣創建結構變量: ```cpp structure_name variable_name ``` 因此,如果您想要使用此結構保存兩名學生的信息,那么您可以這樣做: ```cpp Student s1, s2; ``` 然后我可以像這樣訪問`Student`結構的成員: ```cpp //Assigning name to first student s1.stuName = "Ajeet"; //Assigning age to the second student s2.stuAddr = 22; ``` 同樣,我可以為每個學生設置并獲取結構的其他數據成員的值。讓我們看一個完整的例子來把它們放在一起: ## C++中的結構示例 ```cpp #include <iostream> using namespace std; struct Student{ char stuName[30]; int stuRollNo; int stuAge; }; int main(){ Student s; cout<<"Enter Student Name: "; cin.getline(s.stuName, 30); ?cout<<"ENter Student Roll No: "; ? cin>>s.stuRollNo; cout<<"Enter Student Age: "; cin>>s.stuAge; cout<<"Student Record:"<<endl; cout<<"Name: "<<s.stuName<<endl; cout<<"Roll No: "<<s.stuRollNo<<endl; cout<<"Age: "<<s.stuAge; return 0; } ``` **輸出:** ```cpp Enter Student Name: Negan ENter Student Roll No: 4101003 Enter Student Age: 22 Student Record: Name: Negan Roll No: 4101003 Age: 22 ```
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