# Java 程序：線性搜索 > 原文： [https://beginnersbook.com/2014/04/java-program-for-linear-search-example/](https://beginnersbook.com/2014/04/java-program-for-linear-search-example/) #### 示例程序： 該程序使用[線性搜索算法](https://en.wikipedia.org/wiki/Linear_search)，在用戶輸入的所有其他數字中找出數字。 ```java /* Program: Linear Search Example * Written by: Chaitanya from beginnersbook.com * Input: Number of elements, element's values, value to be searched * 輸出：Position of the number input by user among other numbers*/ import java.util.Scanner; class LinearSearchExample { public static void main(String args[]) { int counter, num, item, array[]; //To capture user input Scanner input = new Scanner(System.in); System.out.println("Enter number of elements:"); num = input.nextInt(); //Creating array to store the all the numbers array = new int[num]; System.out.println("Enter " + num + " integers"); //Loop to store each numbers in array for (counter = 0; counter < num; counter++) array[counter] = input.nextInt(); System.out.println("Enter the search value:"); item = input.nextInt(); for (counter = 0; counter < num; counter++) { if (array[counter] == item) { System.out.println(item+" is present at location "+(counter+1)); /*Item is found so to stop the search and to come out of the * loop use break statement.*/ break; } } if (counter == num) System.out.println(item + " doesn't exist in array."); } } ``` 輸出 1： ```java Enter number of elements: 6 Enter 6 integers 22 33 45 1 3 99 Enter the search value: 45 45 is present at location 3 ``` 輸出 2： ```java Enter number of elements: 4 Enter 4 integers 11 22 4 5 Enter the search value: 99 99 doesn't exist in array. ```