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                # Java - 從`LinkedList`刪除第一個和最后一個元素 > 原文: [https://beginnersbook.com/2014/07/java-remove-first-and-last-element-from-linkedlist-example/](https://beginnersbook.com/2014/07/java-remove-first-and-last-element-from-linkedlist-example/) 在本教程中,我們將學習如何從`LinkedList`中刪除第一個和最后一個元素。在最后幾篇文章中,我們分享了以下教程: 1)[從特定索引中刪除元素](https://beginnersbook.com/2014/07/java-remove-element-from-a-specific-index-in-linkedlist-example/) 2)[從`LinkedList`中刪除特定元素](https://beginnersbook.com/2014/07/java-remove-specific-elements-from-linkedlist-example/) #### 示例 我們使用[`removeFirst()`方法](https://docs.oracle.com/javase/7/docs/api/java/util/LinkedList.html#removeFirst())刪除第一個和[`removeLast()`方法](https://docs.oracle.com/javase/7/docs/api/java/util/LinkedList.html#removeLast())以從`LinkedList`中刪除最后一個元素。方法定義和描述如下: 1)`public E removeFirst()`:從此列表中刪除并返回第一個元素。 2)`public E removeLast()`:刪除并返回此列表中的最后一個元素。 **完整代碼:** ```java import java.util.LinkedList; public class RemoveExample { public static void main(String[] args) { // Create a LinkedList LinkedList<String> linkedlist = new LinkedList<String>(); // Add elements to LinkedList linkedlist.add("Item1"); linkedlist.add("Item2"); linkedlist.add("Item3"); linkedlist.add("Item4"); linkedlist.add("Item5"); // Displaying Elements before remove System.out.println("LinkedList Elements are:"); for(String str: linkedlist){ System.out.println(str); } // Removing First element Object firstElement = linkedlist.removeFirst(); System.out.println("\nElement removed: "+ firstElement); // Removing last Element Object lastElement = linkedlist.removeLast(); System.out.println("Element removed: "+ lastElement); // LinkedList elements after remove System.out.println("\nList Elements after Remove:"); for(String str2: linkedlist){ System.out.println(str2); } } } ``` 輸出: ```java LinkedList Elements are: Item1 Item2 Item3 Item4 Item5 Element removed: Item1 Element removed: Item5 List Elements after Remove: Item2 Item3 Item4 ```
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