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                # C 程序:計算元音,輔音等的數量 > 原文: [https://www.programiz.com/c-programming/examples/vowel-consonant-frequency-string](https://www.programiz.com/c-programming/examples/vowel-consonant-frequency-string) #### 在此示例中,對用戶輸入的字符串中的元音,輔音,數字和空格進行計數。 要理解此示例,您應該了解以下 [C 編程](/c-programming "C tutorial")主題: * [C 數組](/c-programming/c-arrays) * [C 編程字符串](/c-programming/c-strings) * * * ## 計算元音,輔音等的程序 ```c #include <stdio.h> int main() { char line[150]; int vowels, consonant, digit, space; vowels = consonant = digit = space = 0; printf("Enter a line of string: "); fgets(line, sizeof(line), stdin); for (int i = 0; line[i] != '\0'; ++i) { if (line[i] == 'a' || line[i] == 'e' || line[i] == 'i' || line[i] == 'o' || line[i] == 'u' || line[i] == 'A' || line[i] == 'E' || line[i] == 'I' || line[i] == 'O' || line[i] == 'U') { ++vowels; } else if ((line[i] >= 'a' && line[i] <= 'z') || (line[i] >= 'A' && line[i] <= 'Z')) { ++consonant; } else if (line[i] >= '0' && line[i] <= '9') { ++digit; } else if (line[i] == ' ') { ++space; } } printf("Vowels: %d", vowels); printf("\nConsonants: %d", consonant); printf("\nDigits: %d", digit); printf("\nWhite spaces: %d", space); return 0; } ``` **輸出** ```c Enter a line of string: adfslkj34 34lkj343 34lk Vowels: 1 Consonants: 11 Digits: 9 White spaces: 2 ``` 在此,用戶輸入的字符串存儲在`line`變量中。 首先,將變量`vowels`,`consonant`,`digit`和`space`初始化為 0。 然后,使用`for`循環迭代字符串的字符。 在每次迭代中,都會檢查字符是否為元音,輔音,數字和空格。 假設字符是元音,在這種情況下,`vowel`變量增加 1。 循環結束時,元音,輔音,數字和空格的數量分別存儲在變量`vowels`,`consonant`,`digit`和`space`。
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