# C 程序：通過將結構傳遞給函數來相加兩個復數 > 原文： [https://www.programiz.com/c-programming/examples/complex-number-add](https://www.programiz.com/c-programming/examples/complex-number-add) #### 在此示例中，您將學習將兩個復數用作結構并通過創建用戶定義的函數將它們相加。 要理解此示例，您應該了解以下 [C 編程](/c-programming "C tutorial")主題： * [C 結構](/c-programming/c-structures) * [C 結構和函數](/c-programming/c-structure-function) * * * ## 加兩個復數 ```c #include <stdio.h> typedef struct complex { float real; float imag; } complex; complex add(complex n1, complex n2); int main() { complex n1, n2, result; printf("For 1st complex number \n"); printf("Enter the real and imaginary parts: "); scanf("%f %f", &n1.real, &n1.imag); printf("\nFor 2nd complex number \n"); printf("Enter the real and imaginary parts: "); scanf("%f %f", &n2.real, &n2.imag); result = add(n1, n2); printf("Sum = %.1f + %.1fi", result.real, result.imag); return 0; } complex add(complex n1, complex n2) { complex temp; temp.real = n1.real + n2.real; temp.imag = n1.imag + n2.imag; return (temp); } ``` **輸出** ```c For 1st complex number Enter the real and imaginary parts: 2.1 -2.3 For 2nd complex number Enter the real and imaginary parts: 5.6 23.2 Sum = 7.7 + 20.9i ``` 在該程序中，聲明了一個名為`complex`的結構。 它具有兩個成員：`real`和`imag`。 然后，我們從該結構創建了兩個變量`n1`和`n2`。 這兩個結構變量將傳遞給`add()`函數。 該函數計算總和并返回包含該總和的結構。 最后，從`main()`函數打印出復數的總和。