# C++ 程序：使用結構相加兩個距離（以英寸和英尺為單位） > 原文： [https://www.programiz.com/cpp-programming/examples/inch-feet-structure](https://www.programiz.com/cpp-programming/examples/inch-feet-structure) #### 該程序需要兩個距離（以英寸和英尺為單位），將其相加并在屏幕上顯示結果。 要理解此示例，您應該了解以下 [C++ 編程](/cpp-programming "C++ tutorial")主題： * [C++ 結構](/cpp-programming/structure) * [C++ `if`，`if...else`和嵌套`if...else`](/cpp-programming/if-else) * * * * * * ## 示例：使用結構相加距離 ```cpp #include <iostream> using namespace std; struct Distance{ int feet; float inch; }d1 , d2, sum; int main() { cout << "Enter 1st distance," << endl; cout << "Enter feet: "; cin >> d1.feet; cout << "Enter inch: "; cin >> d1.inch; cout << "\nEnter information for 2nd distance" << endl; cout << "Enter feet: "; cin >> d2.feet; cout << "Enter inch: "; cin >> d2.inch; sum.feet = d1.feet+d2.feet; sum.inch = d1.inch+d2.inch; // changing to feet if inch is greater than 12 if(sum.inch > 12) { ++ sum.feet; sum.inch -= 12; } cout << endl << "Sum of distances = " << sum.feet << " feet " << sum.inch << " inches"; return 0; } ``` **輸出** ```cpp Enter 1st distance, Enter feet: 6 Enter inch: 3.4 Enter information for 2nd distance Enter feet: 5 Enter inch: 10.2 Sum of distances = 12 feet 1.6 inches ``` 在此程序中，聲明了一個包含兩個數據成員（`feet`和`inch`）的結構`Distance`，以英寸-英尺系統存儲距離。 在此，創建兩個結構變量`d1`和`d2`來存儲用戶輸入的距離。 并且，`sum`變量存儲距離之和。 如果`sum`變量的`feet`的值大于 12，則`if..else`語句用于將英寸轉換為英尺。