# Python 程序：檢查閏年 > 原文： [https://www.programiz.com/python-programming/examples/leap-year](https://www.programiz.com/python-programming/examples/leap-year) #### 在該程序中，您將學習檢查年份是否為閏年。 我們將使用嵌套`if...else`解決此問題。 要理解此示例，您應該了解以下 [Python 編程](/python-programming "Python tutorial")主題： * [Python 運算符](/python-programming/operators) * [Python `if...else`語句](/python-programming/if-elif-else) * * * 除世紀年份（以 00 結尾的年份）外，閏年可精確地除以 4。 只有將世紀完全除以 400，世紀年才是閏年。例如， ```py 2017 is not a leap year 1900 is a not leap year 2012 is a leap year 2000 is a leap year ``` ## 源代碼 ```py # Python program to check if year is a leap year or not year = 2000 # To get year (integer input) from the user # year = int(input("Enter a year: ")) if (year % 4) == 0: if (year % 100) == 0: if (year % 400) == 0: print("{0} is a leap year".format(year)) else: print("{0} is not a leap year".format(year)) else: print("{0} is a leap year".format(year)) else: print("{0} is not a leap year".format(year)) ``` **輸出** ```py 2000 is a leap year ``` 您可以在源代碼中更改`year`的值，然后再次運行以測試該程序。