# 數組范圍的平均值 > 原文： [https://www.geeksforgeeks.org/mean-range-array/](https://www.geeksforgeeks.org/mean-range-array/) 給定 n 個整數數組。 給出 q 個查詢。 編寫一個程序，在新行中為每個查詢打印從 l 到 r 范圍內的均值的下限值。 **示例**： ``` Input : arr[] = {1, 2, 3, 4, 5} q = 3 0 2 1 3 0 4 Output : 2 3 3 Here for 0 to 2 (1 + 2 + 3) / 3 = 2 Input : arr[] = {6, 7, 8, 10} q = 2 0 3 1 2 Output : 7 7 ``` **樸素的方法**：我們可以為每個查詢 l 到 r 運行循環，并找到范圍內元素的總和和數量。 此后，我們可以為每個查詢打印均值下限。 ## C++ ```cpp // CPP program to find floor value // of mean in range l to r #include <bits/stdc++.h> using namespace std; // To find mean of range in l to r int findMean(int arr[], int l, int r) { ????// Both sum and count are ????// initialize to 0 ????int sum = 0, count = 0; ????// To calculate sum and number ????// of elements in range l to r ????for (int i = l; i <= r; i++) { ????????sum += arr[i]; ????????count++; ????} ????// Calculate floor value of mean ????int mean = floor(sum / count); ????// Returns mean of array ????// in range l to r ????return mean; } // Driver program to test findMean() int main() { ????int arr[] = { 1, 2, 3, 4, 5 }; ????cout << findMean(arr, 0, 2) << endl; ????cout << findMean(arr, 1, 3) << endl; ????cout << findMean(arr, 0, 4) << endl; ????return 0; } ```