# 形成矩陣線圈 > 原文： [https://www.geeksforgeeks.org/form-coils-matrix/](https://www.geeksforgeeks.org/form-coils-matrix/) 給定一個正整數 n，該整數表示 4n x 4n 矩陣的維，值從 1 到 n 從左到右，從上到下填充。 從矩陣形成兩個線圈，然后打印線圈。 例子： ``` Input : n = 1; Output : Coil 1 : 10 6 2 3 4 8 12 16 Coil 2 : 7 11 15 14 13 9 5 1 Explanation : Matrix is 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 Input : n = 2; Output : Coil 1 : 36 28 20 21 22 30 38 46 54 53 52 51 50 42 34 26 18 10 2 3 4 5 6 7 8 16 24 32 40 48 56 64 Coil 2 : 29 37 45 44 43 35 27 19 11 12 13 14 15 23 31 39 47 55 63 62 61 60 59 58 57 49 41 33 25 17 9 1 ``` 矩陣中的元素總數為 16n ² 。 所有元件均分為兩個線圈。 每個線圈具有 8n ² 個元素。 我們制作兩個這樣大小的數組。 我們首先以給定的順序遍歷來填充線圈 1 中的元素。 一旦我們在線圈 1 中填充了元素，就可以使用公式 coil2 [i] = 16 * n * n +1 -coil1 [i]獲得其他線圈 2 的元素。 ## C++ ```cpp // C++ program to print 2 coils of a // 4n x 4n matrix. #include<iostream> using namespace std; // Print coils in a matrix of size 4n x 4n? void printCoils(int n) { ????// Number of elements in each coil ????int m = 8*n*n; ????// Let us fill elements in coil 1\. ????int coil1[m]; ????// First element of coil1 ????// 4*n*2*n + 2*n; ????coil1[0] = 8*n*n + 2*n; ????int curr = coil1[0]; ????int nflg = 1, step = 2; ????// Fill remaining m-1 elements in coil1[] ????int index = 1; ????while (index < m) ????{ ????????// Fill elements of current step from ????????// down to up ????????for (int i=0; i<step; i++) ????????{ ????????????// Next element from current element ????????????curr = coil1[index++] = (curr - 4*n*nflg); ????????????if (index >= m) ????????????????break; ????????} ????????if (index >= m) ????????????break; ????????// Fill elements of current step from ????????// up to down. ????????for (int i=0; i<step; i++) ????????{ ????????????curr = coil1[index++] = curr + nflg; ????????????if (index >= m) ????????????????break; ????????} ????????nflg = nflg*(-1); ????????step += 2; ????} ????/* get coil2 from coil1 */ ????int coil2[m]; ????for (int i=0; i<8*n*n; i++) ????????coil2[i] = 16*n*n + 1 -coil1[i]; ????// Print both coils ????cout << "Coil 1 : "; ????for(int i=0; i<8*n*n; i++) ????????cout << coil1[i] << " "; ????cout << "\nCoil 2 : "; ????for (int i=0; i<8*n*n; i++) ????????cout << coil2[i] << " "; } // Driver code int main() { ????int n = 1; ????printCoils(n); ????return 0; } ``` ## Java ```java // Java program to print 2 coils? // of a 4n x 4n matrix. class GFG { ????// Print coils in a matrix of size 4n x 4n ????static void printCoils(int n)? ????{ ????????// Number of elements in each coil ????????int m = 8 * n * n; ????????// Let us fill elements in coil 1\. ????????int coil1[] = new int[m]; ????????// First element of coil1 ????????// 4*n*2*n + 2*n; ????????coil1[0] = 8 * n * n + 2 * n; ????????int curr = coil1[0]; ????????int nflg = 1, step = 2; ????????// Fill remaining m-1 elements in coil1[] ????????int index = 1; ????????while (index < m) ????????{ ????????????// Fill elements of current step from ????????????// down to up ????????????for (int i = 0; i < step; i++)? ????????????????{ ????????????????????// Next element from current element ????????????????????curr = coil1[index++] = (curr - 4 * n * nflg); ????????????????????if (index >= m) ????????????????????break; ????????????????} ????????????if (index >= m) ????????????????break; ????????????// Fill elements of current step from ????????????// up to down. ????????????for (int i = 0; i < step; i++)? ????????????{ ????????????????curr = coil1[index++] = curr + nflg; ????????????????if (index >= m) ????????????????break; ????????????} ????????????nflg = nflg * (-1); ????????????step += 2; ????????} ????????/* get coil2 from coil1 */ ????????int coil2[] = new int[m]; ????????for (int i = 0; i < 8 * n * n; i++) ????????????coil2[i] = 16 * n * n + 1 - coil1[i]; ????????// Print both coils ????????System.out.print("Coil 1 : "); ????????for (int i = 0; i < 8 * n * n; i++) ????????????System.out.print(coil1[i] + " "); ????????System.out.print("\nCoil 2 : "); ????????for (int i = 0; i < 8 * n * n; i++) ????????????System.out.print(coil2[i] + " "); ????} ????// Driver code ????public static void main(String[] args) ????{ ????????int n = 1; ????????printCoils(n); ????} } // This code is contributed by Anant Agarwal. ``` ## Python3 ```py # Python3 program to pr2 coils of a # 4n x 4n matrix. # Prcoils in a matrix of size 4n x 4n? def printCoils(n): ????# Number of elements in each coil ????m = 8*n*n ????# Let us fill elements in coil 1\. ????coil1 = [0]*m ????# First element of coil1 ????# 4*n*2*n + 2*n ????coil1[0] = 8*n*n + 2*n ????curr = coil1[0] ????nflg = 1 ????step = 2 ????# Fill remaining m-1 elements in coil1[] ????index = 1 ????while (index < m): ????????# Fill elements of current step from ????????# down to up ????????for i in range(step): ????????????# Next element from current element ????????????curr = coil1[index] = (curr - 4*n*nflg) ????????????index += 1 ????????????if (index >= m): ????????????????break ????????if (index >= m): ????????????break ????????# Fill elements of current step from ????????# up to down. ????????for i in range(step): ????????????curr = coil1[index] = curr + nflg ????????????index += 1 ????????????if (index >= m): ????????????????break ????????nflg = nflg*(-1) ????????step += 2 ????#get coil2 from coil1 */ ????coil2 = [0]*m ????i = 0 ????while(i < 8*n*n): ????????coil2[i] = 16*n*n + 1 -coil1[i] ????????i += 1 ????# Prboth coils ????print("Coil 1 :", end = " ") ????i = 0 ????while(i < 8*n*n): ????????print(coil1[i], end = " ") ????????i += 1 ????print("\nCoil 2 :", end = " ") ????i = 0 ????while(i < 8*n*n): ????????print(coil2[i], end = " ") ????????i += 1 # Driver code n = 1 printCoils(n) # This code is contributed by shubhamsingh10 ``` ## C# ```cs // C# program to print 2 coils? // of a 4n x 4n matrix. using System; class GFG { ????// Print coils in a matrix of ????// size 4n x 4n ????static void printCoils(int n)? ????{ ????????// Number of elements in ????????// each coil ????????int m = 8 * n * n; ????????// Let us fill elements in ????????// coil 1\. ????????int [] coil1 = new int[m]; ????????// First element of coil1 ????????// 4*n*2*n + 2*n; ????????coil1[0] = 8 * n * n + 2 * n; ????????int curr = coil1[0]; ????????int nflg = 1, step = 2; ????????// Fill remaining m-1 elements ????????// in coil1[] ????????int index = 1; ????????while (index < m) ????????{ ????????????// Fill elements of current ????????????// step from down to up ????????????for (int i = 0; i < step; i++)? ????????????????{ ????????????????????// Next element from? ????????????????????// current element ????????????????????curr = coil1[index++]? ????????????????????= (curr - 4 * n * nflg); ????????????????????if (index >= m) ????????????????????????break; ????????????????} ????????????if (index >= m) ????????????????break; ????????????// Fill elements of current step ????????????// from up to down. ????????????for (int i = 0; i < step; i++)? ????????????{ ????????????????curr = coil1[index++] = curr? ?????????????????????????????????????+ nflg; ????????????????if (index >= m) ????????????????????break; ????????????} ????????????nflg = nflg * (-1); ????????????step += 2; ????????} ????????/* get coil2 from coil1 */ ????????int [] coil2 = new int[m]; ????????for (int i = 0; i < 8 * n * n; i++) ????????????coil2[i] = 16 * n * n + 1 - coil1[i]; ????????// Print both coils ????????Console.Write("Coil 1 : "); ????????for (int i = 0; i < 8 * n * n; i++) ????????????Console.Write(coil1[i] + " "); ????????Console.Write("\nCoil 2 : "); ????????for (int i = 0; i < 8 * n * n; i++) ????????????Console.Write(coil2[i] + " "); ????} ????// Driver code ????public static void Main() ????{ ????????int n = 1; ????????printCoils(n); ????} } // This code is contributed by KRV. ``` ## PHP ```php <?php // PHP program to print 2 coils of a // 4n x 4n matrix. // Print coils in a matrix of size 4n x 4n? function printCoils( $n) { ????// Number of elements in each coil ????$m = 8 * $n * $n; ????// Let us fill elements in coil 1\. ????$coil1 = array(); ????// First element of coil1 ????// 4*n*2*n + 2*n; ????$coil1[0] = 8 * $n * $n + 2 * $n; ????$curr = $coil1[0]; ????$nflg = 1; $step = 2; ????// Fill remaining m-1 elements in coil1[] ????$index = 1; ????while ($index < $m) ????{ ????????// Fill elements of current step from ????????// down to up ????????for ( $i = 0; $i < $step; $i++) ????????{ ????????????// Next element from current element ????????????$curr = $coil1[$index++] =? ?????????????????????($curr - 4*$n*$nflg); ????????????if ($index >= $m) ????????????????break; ????????} ????????if ($index >= $m) ????????????break; ????????// Fill elements of current step from ????????// up to down. ????????for ( $i=0; $i<$step; $i++) ????????{ ????????????$curr = $coil1[$index++] =? ????????????????????????????$curr + $nflg; ????????????if ($index >= $m) ????????????????break; ????????} ????????$nflg = $nflg * (-1); ????????$step += 2; ????} ????/* get coil2 from coil1 */ ????$coil2 = array(); ????for ( $i = 0; $i < 8 * $n * $n; $i++) ????????$coil2[$i] = 16 * $n * $n + 1 -$coil1[$i]; ????// Print both coils ????echo "Coil 1 : "; ????for( $i = 0; $i < 8 * $n * $n; $i++) ????echo $coil1[$i] , " "; ????echo "\nCoil 2 : "; ????for ( $i = 0; $i < 8 * $n * $n; $i++) ????????echo $coil2[$i] , " "; } // Driver code $n = 1; printCoils($n); // This code is contributed by anuj_67\. ?> ``` Output: ``` Coil 1 : 10 6 2 3 4 8 12 16 Coil 2 : 7 11 15 14 13 9 5 1 ``` 在**中詢問 Yahoo**