<ruby id="bdb3f"></ruby>

    <p id="bdb3f"><cite id="bdb3f"></cite></p>

      <p id="bdb3f"><cite id="bdb3f"><th id="bdb3f"></th></cite></p><p id="bdb3f"></p>
        <p id="bdb3f"><cite id="bdb3f"></cite></p>

          <pre id="bdb3f"></pre>
          <pre id="bdb3f"><del id="bdb3f"><thead id="bdb3f"></thead></del></pre>

          <ruby id="bdb3f"><mark id="bdb3f"></mark></ruby><ruby id="bdb3f"></ruby>
          <pre id="bdb3f"><pre id="bdb3f"><mark id="bdb3f"></mark></pre></pre><output id="bdb3f"></output><p id="bdb3f"></p><p id="bdb3f"></p>

          <pre id="bdb3f"><del id="bdb3f"><progress id="bdb3f"></progress></del></pre>

                <ruby id="bdb3f"></ruby>

                合規國際互聯網加速 OSASE為企業客戶提供高速穩定SD-WAN國際加速解決方案。 廣告
                # 用于添加兩個矩陣的程序 > 原文: [https://www.geeksforgeeks.org/c-program-addition-two-matrices/](https://www.geeksforgeeks.org/c-program-addition-two-matrices/) ![](https://img.kancloud.cn/32/7e/327eb2eded245996aa66396c7112a0d3_1024x512.png) 下面的程序添加了兩個大小為 4 * 4 的正方形矩陣,我們可以將 N 更改為不同的維度。 ## C++ ```cpp // C++ program for addition? // of two matrices #include <bits/stdc++.h> using namespace std; #define N 4? // This function adds A[][] and B[][], and stores? // the result in C[][]? void add(int A[][N], int B[][N], int C[][N])? {? ????int i, j;? ????for (i = 0; i < N; i++)? ????????for (j = 0; j < N; j++)? ????????????C[i][j] = A[i][j] + B[i][j];? }? // Driver code int main()? {? ????int A[N][N] = { {1, 1, 1, 1},? ????????????????????{2, 2, 2, 2},? ????????????????????{3, 3, 3, 3},? ????????????????????{4, 4, 4, 4}};? ????int B[N][N] = { {1, 1, 1, 1},? ????????????????????{2, 2, 2, 2},? ????????????????????{3, 3, 3, 3},? ????????????????????{4, 4, 4, 4}};? ????int C[N][N]; // To store result? ????int i, j;? ????add(A, B, C);? ????cout << "Result matrix is " << endl;? ????for (i = 0; i < N; i++)? ????{? ????????for (j = 0; j < N; j++)? ????????cout << C[i][j] << " ";? ????????cout << endl; ????}? ????return 0;? }? // This code is contributed by rathbhupendra ``` ## C ``` #include <stdio.h> #define N 4 // This function adds A[][] and B[][], and stores // the result in C[][] void add(int A[][N], int B[][N], int C[][N]) { ????int i, j; ????for (i = 0; i < N; i++) ????????for (j = 0; j < N; j++) ????????????C[i][j] = A[i][j] + B[i][j]; } int main() { ????int A[N][N] = { {1, 1, 1, 1}, ????????????????????{2, 2, 2, 2}, ????????????????????{3, 3, 3, 3}, ????????????????????{4, 4, 4, 4}}; ????int B[N][N] = { {1, 1, 1, 1}, ????????????????????{2, 2, 2, 2}, ????????????????????{3, 3, 3, 3}, ????????????????????{4, 4, 4, 4}}; ????int C[N][N]; // To store result ????int i, j; ????add(A, B, C); ????printf("Result matrix is \n"); ????for (i = 0; i < N; i++) ????{ ????????for (j = 0; j < N; j++) ???????????printf("%d ", C[i][j]); ????????printf("\n"); ????} ????return 0; } ``` ## Java ```java // Java program for addition? // of two matrices class GFG { ????static final int N = 4; ????// This function adds A[][] and B[][], and stores ????// the result in C[][] ????static void add(int A[][], int B[][], int C[][]) ????{ ????????int i, j; ????????for (i = 0; i < N; i++) ????????????for (j = 0; j < N; j++) ????????????????C[i][j] = A[i][j] + B[i][j]; ????} ????// Driver code ????public static void main (String[] args) ????{ ????????int A[][] = { {1, 1, 1, 1}, ????????????????????????{2, 2, 2, 2}, ????????????????????????{3, 3, 3, 3}, ????????????????????????{4, 4, 4, 4}}; ????????int B[][] = { {1, 1, 1, 1}, ????????????????????????{2, 2, 2, 2}, ????????????????????????{3, 3, 3, 3}, ????????????????????????{4, 4, 4, 4}}; ????????// To store result ????????int C[][] = new int[N][N];? ????????int i, j; ????????add(A, B, C); ????????System.out.print("Result matrix is \n"); ????????for (i = 0; i < N; i++) ????????{ ????????????for (j = 0; j < N; j++) ????????????System.out.print(C[i][j] + " "); ????????????System.out.print("\n"); ????????} ????} } // This code is contributed by Anant Agarwal. ``` ## Python3 ```py # Python3 program for addition? # of two matrices N = 4 # This function adds A[][] # and B[][], and stores # the result in C[][] def add(A,B,C): ????for i in range(N): ????????for j in range(N): ????????????C[i][j] = A[i][j] + B[i][j] # driver code A = [ [1, 1, 1, 1], ????[2, 2, 2, 2], ????[3, 3, 3, 3], ????[4, 4, 4, 4]] B= [ [1, 1, 1, 1], ????[2, 2, 2, 2], ????[3, 3, 3, 3], ????[4, 4, 4, 4]] C=A[:][:] # To store result add(A, B, C) print("Result matrix is") for i in range(N): ????for j in range(N): ????????print(C[i][j], " ", end='') ????print() # This code is contributed # by Anant Agarwal. ``` ## C# ```cs // C# program for addition? // of two matrices using System; class GFG { ????static int N = 4; ????// This function adds A[][] and B[][], and stores ????// the result in C[][] ????static void add(int[,] A, int [,]B, int [,]C) ????{ ????????int i, j; ????????for (i = 0; i < N; i++) ????????????for (j = 0; j < N; j++) ????????????????C[i,j] = A[i,j] + B[i,j]; ????} ????// Driver code ????public static void Main () ????{ ????????int [,]A = { {1, 1, 1, 1}, ????????????????????????{2, 2, 2, 2}, ????????????????????????{3, 3, 3, 3}, ????????????????????????{4, 4, 4, 4}}; ????????int [,]B = { {1, 1, 1, 1}, ????????????????????????{2, 2, 2, 2}, ????????????????????????{3, 3, 3, 3}, ????????????????????????{4, 4, 4, 4}}; ????????// To store result ????????int [,]C = new int[N,N];? ????????int i, j; ????????add(A, B, C); ????Console.WriteLine("Result matrix is "); ????????for (i = 0; i < N; i++) ????????{ ????????????for (j = 0; j < N; j++) ????????????Console.Write(C[i,j] + " "); ????????????Console.WriteLine(); ????????} ????} } // This code is contributed by vt_m. ``` ## PHP ```php <?php // This function adds A[][] and? // B[][], and stores the result in C[][] function add(&$A, &$B, &$C) { ????$N = 4; ????for ($i = 0; $i < $N; $i++) ????????for ($j = 0; $j < $N; $j++) ????????????$C[$i][$j] = $A[$i][$j] +? ?????????????????????????$B[$i][$j]; } // Driver code $A = array(array(1, 1, 1, 1), ???????????array(2, 2, 2, 2), ???????????array(3, 3, 3, 3), ???????????array(4, 4, 4, 4)); $B = array(array(1, 1, 1, 1), ???????????array(2, 2, 2, 2), ???????????array(3, 3, 3, 3), ???????????array(4, 4, 4, 4)); $N = 4; add($A, $B, $C); echo "Result matrix is \n"; for ($i = 0; $i < $N; $i++) { ????for ($j = 0; $j < $N; $j++) ????{ ????????echo $C[$i][$j]; ????????echo " "; ????} ????echo "\n" ; } // This code is contributed? // by Shivi_Aggarwal ?> ``` **輸出**: ``` Result matrix is 2 2 2 2 4 4 4 4 6 6 6 6 8 8 8 8 ``` 該程序可以擴展為矩形矩陣。 以下帖子對于擴展該程序很有用。 [如何在 C 中將 2D 數組作為參數傳遞?](https://www.geeksforgeeks.org/pass-2d-array-parameter-c/) 上述程序的時間復雜度是 `O(n^2)`。
                  <ruby id="bdb3f"></ruby>

                  <p id="bdb3f"><cite id="bdb3f"></cite></p>

                    <p id="bdb3f"><cite id="bdb3f"><th id="bdb3f"></th></cite></p><p id="bdb3f"></p>
                      <p id="bdb3f"><cite id="bdb3f"></cite></p>

                        <pre id="bdb3f"></pre>
                        <pre id="bdb3f"><del id="bdb3f"><thead id="bdb3f"></thead></del></pre>

                        <ruby id="bdb3f"><mark id="bdb3f"></mark></ruby><ruby id="bdb3f"></ruby>
                        <pre id="bdb3f"><pre id="bdb3f"><mark id="bdb3f"></mark></pre></pre><output id="bdb3f"></output><p id="bdb3f"></p><p id="bdb3f"></p>

                        <pre id="bdb3f"><del id="bdb3f"><progress id="bdb3f"></progress></del></pre>

                              <ruby id="bdb3f"></ruby>

                              哎呀哎呀视频在线观看